Updated: Jan 10, 2001. Copyright 2000 by Jacob Bear, Haifa, Israel. All Rights Reserved.
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MODELING GROUNDWATER FLOW AND CONTAMINANT TRANSPORT |
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Professor EmeritusFaculty of Civil EngineeringTechnion-Israel Institute of TechnologyHaifa 32000, Israel
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TOPIC B was devoted to the MOTION EQUATION. We have presented
this equation for the two basic flow models:
TOPIC D:
MODELING FLOW IN AQUIFERS
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In both flow "modes", we have considered extensions of the original (experimentally derived) Darcy's law, viz., extensions to
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In all cases, we have shown how the specific discharge is related to the piezometric head, or to the fluid's pressure.
The first natural question,
especially if at some earlier studies of basic groundwater flow you have used
Darcy's law to solve some simple flow problems, is:
IS DARCY'S LAW SUFFICIENT FOR SOLVING GROUND WATER FLOW PROBLEMS, OR IS THERE A NEED FOR ADDITIONAL INFORMATION, OR EQUATION(S)?
Typically, in three-dimensional
flow, the specific discharge vector is expressed by:
in which we have TWO state variables:
The specific discharge
The piezometric head
Equation (1) is written as a vector equation (instead of writing three scalar ones). The dot indicates a dot product. Just to make sure that you understand this nomenclature,
Eqn (1) as scalar equations. For the sake of simplicity, assume that the soil is anisotropic, but that x, y, z are principal directions. ANSWERRecall that the main objective of modeling flow in a given porous medium, or aquifer domain, is to predict the spatial and temporal distribution of the piezometric head,
h = h (x, y, z, t), within the domain, in response to excitation of the domain (= the system).Later we shall discuss in detail the meaning of "excitation". Here, think of "excitation" as what we do to the system (e.g., pump from it or inject into it) in order to achieve goals.
To predict the distribution of
The specific discharge vector
The piezometric head
However, the only available
vector equation seems to be Darcy's law,
q = - K Ñh, (1)
given above. How can we solve a single equation for two variables?
Note
that we could say that we have FOUR unknown scalar variables: qx,
qy, qz,
and h
qx = -
K
, qy
= - K
, qz
= - K
.
(2)
We have written these equations for the case of an isotropic porous medium domain. However, you should have no difficulty in writing the three scalar equations for an anisotropic one. TRY. If you do not remember how to express Darcy's law in a scalar form for an anisotropic porous medium, Click here.
Again, UNFORTUNATELY, we have
only THREE SCALAR EQUATIONS . We know that it is

Accordingly, we have to discuss
the requirement that the balance of fluid mass be maintained within a considered
porous medium domain. We shall express this requirement in the form of a 'mass
balance equation'. Later we shall see that the description
of transport of a chemical species in a fluid phase requires that a mass balance
of that species be also satisfied.

Our objective is to develop the mass
balance equation. We intend to do it for one, two, and three fluid phases in
a porous medium domain. Deformation of the solid matrix will also be taken into
account. For a given fluid phase, by combining the mass balance equation with an
appropriate motion equation, a flow
equation for that phase is obtained. The complete flow
model requires, in addition, specification of appropriate initial and boundary
conditions. Also, the numerical values of all the coefficients which appear in
the model equations must be specified. All this supplemental information must be
specified for the considered domain and fluids, in order to obtain solutions
that pertain to the particular flow problem under consideration.
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LECTURE 1: Fundamental Balance Equation
Following the above introductory remarks, I suggest that we proceed in the following steps:
Although our direct objective is to
develop a balance equation, for the mass of a fluid phase, since the same
development and principles apply also to the balance of any extensive quantity
(e.g., energy, or mass of a component of a fluid phase), we shall start by
considering the most general balance equation for ANY
In
To provide such information, we
shall express the balance equation in the form of
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Let me remind you:
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Remember that we are interested in
developing the mass balance equation, or the balance equation for any extensive
quantities, at the
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(In parenthesis, we need to discuss the meaning of "averaging" as a tool for passing from the microscopic level to the macroscopic one. However, at this stage, just think of the intuitive meaning of the word. We may come back to this topic at a later stage.). Or,
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In fact, the same approach, of developing the balance equation directly, is valid also when developing the balance equation at the microscopic level, also considered as a continuum.
Accordingly, let us start by
developing the balance equation at the microscopic level. This means that we are
considering what happens at every point

However, as suggested above, before discussing the specific subject of "mass balance equation", we shall, first, discuss the more general case of a balance equation for any extensive quantity. It will then be a straightforward procedure to apply the results to the particular case in which the mass of a phase is the considered extensive quantity.
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The basic idea of a balance is
very simple and straightforward:
A balance can be written for any
extensive quantity,
Let us denote the time interval by

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Does this make sense?
Let us consider these BALANCE
COMPONENTS in detail:

The components of JtE
are:
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DIVERGENCE OF A FLUX
Let us introduce at this time
the mathematical term
Consider the parallelepiped control
volume with dimensions Dx,
Dy, Dz,
shown in the figure below.

Figure 1: A control volume
During a period Dt,
the excess of inflow over outflow of the considered extensive quantity,
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The excess of inflow over outflow of
the considered extensive quantity,
.gif)
Next, we divide by DxDyDz,
in order to obtain the excess of inflow over outflow of the considered extensive
quantity,
.gif)
Next we wish to learn "what is
this excess at a point. To achieve this goal, we go to the limit of the
above expression , as Dx,Dy,Dz
0. We obtain:
.gif)
Recalling the definition of a
derivative:
.gif)
We may now write:
.gif)
In mathematics, given a vector,
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The two expressions are equivalent!
In words, we say "divergence
of the vector
In defining the divergence of any
vector,

In polar coordinates:
r, q..gif)

To summarize
:
The excess of inflow over outflow of
an extensive quantity, per unit volume and per unit time, is expressed by
Using the above expression, and recalling
the general structure of the partial differential form of the balance equation,
we can immediately write the balance of any extensive quantity without the need
to develop it from first principles. Let me suggest the (strange?!) form
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This does not look like a "normal" equation. Doesn't it? NEVERTHELESS, ...
Whenever you need to write a balance
equation, you have to determine:
And using the above "verbal equation", you'll be able to write the differential form of the balance equation IMMEDIATELY.
Note, and never forget to put, the
dot after the nabla symbol. This will mean that the "nabla dot" symbol
indicates divergence of a vector, while without the dot, we have the gradient
of a scalar (e.g., Ñh).
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DIFFUSIVE FLUX
We still need to discuss the meaning
of "velocity
For the case
E = m, i.e., the extensive quantity is the mass of a phase,VE º Vm º V . (13)
This is rather simple. Thus, Vm
, also denoted by the symbol V, is the velocity of the mass continuum of a phase.
However, consider the example:
E = mg,
e = rg.,
i.e., the extensive quantity is the mass of a g-component
in a phase. What is then the meaning of VE
= Vg?
This g-component
is composed of many molecules which move continuously within the phase (random,
Brownian motion). As discussed in TOPIC
A, LECTURE 2, at the molecular level, we
"see" the individual molecules running around. However, we are not
interested in the detailed behavior at such level. Instead, we average the
behavior of the many individual molecules that run around, within small representative
elementary volumes, called micro-REV (mREV),
and assign the result to the centroid of each such mREV.
In this way, the individual molecules "disappear", and we obtain at
every point only the average behavior. For example, we get the average density, rg,
and the average velocity, Vg.
In other words, we replace the domain with molecules by a domain with a FLUID
that has properties derived by averaging properties of the molecules.
Altogether, at every point within a
phase, now considered as a continuum, we have two velocities:
V
of the mass of the phase as a whole, regarded as a continuum, and
Vg
of the mass of the g-component
also regarded as a continuum.
The two continua occupy the same spatial domain. At every point within the latter, we have properties of both continua.
Also, we have to consider the
fluxes:
The mass flux, rV,
and
The flux of the mass of the g-component,
rgVg.
However, how do we
determine the velocity Vg
?
T
We may now return
to the fundamental balance equation and rewrite it, making use of the above
decomposition:
= -Ñ (eV + JE)
+ rG E,
JE = e(VE
- V).
(16)
This is the most general differential
balance equation for any extensive quantity, E.
Again, it is a balance at a point, in the sense that it describes what
happens on the average within a small volume surrounding the point, with
all values assigned to the point.
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We have, thus, achieved the goal of
stating the general differential balance equation for any extensive quantity, E.
In the next lecture, we'll return to the balance of mass of a fluid phase.
Before turning to the next
lecture, let's rewrite the general balance equation, written above in a vector
form, in terms of the more commonly used coordinate systems
A. Cartesian coordinates:
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At a later stage, we'll discuss how to express the velocity and the diffusive flux.
B. Cylindrical coordinates:

Based on the discussion at the microscopic level, the
E balance equation at the macroscopic level, can be stated in the form:.gif)
In this equation:
The quantity of
(E
per unit volume of porous medium) =
The rate of increase in this
quantity is expressed by
. This term
appears on the l.h.s.
The total E
flux at the macroscopic level is expressed by
,
where the symbol
represents the
intrinsic phase

However, if there exists also
transfer of
Altogether,
we may now write the macroscopic mass balance equation in the form:
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I hope you can now interpret each term in the above equation as a symbolic expression of the rate at which the quantity of E is added per unit volume of porous medium.
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Now to the second approach:
BY AVERAGING
Let's start by writing the
microscopic balance equation for an extensive quantity
= -Ñ (eV + JE)
+ rG E.
(20)
Again, each term expresses the
rate at which the quantity of E is added per unit volume, but this time, it is per unit volume of the fluid.
Let's consider the case in which the
considered fluid phase is occupying only part of the void space, at volumetric
fraction,

vanishes. If it is material with respect to mass, e(V - u) vanishes, and the flux through the Sab-surface is due to diffusion only.
What is a "material surface"?
A "material
surface with respect to an E-quantity"
is surface such that no E-quantity
crosses it. One may also have a

The figure below shows an interface, its velocity, the unit normal vector and the advective flux.

Denoting this interface transfer term by
,
we may rewrite Eqn. (21) in the form
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Physical interpretation: The
net added quantity, represented by the term on the l.h.s, is due to the r.h.s.
terms:
A net influx of E,
per unit time and per unit volume of porous medium, due to spatial
variations in the total
E -flux.
A quantity of E
that leaves the phase through the Sab-surface
that bounds the phase within the REV (of volume U0),
per unit time and per unit volume of porous medium.
deviations of the density and the velocity (at the microscopic level) from
their respective averages.
A diffusive flux,
obtained
as the average of the microscopic one (and, again, multiplied by
Note that, obviously, we have
arrived at the same equation by the two approaches.
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We have now the general
differential form of the macroscopic balance equation for any
within an
a-phase, in a (possibly) multiphase system.
To check if you have understood the above discussion, consider
the case in which we consider the transport of the mass of a g-component
in an a-fluid
phase (of density r).
The g-component
is produced at the rate Gg.
Let c denote
the mass concentration of the g-component
in the a-phase.
Use the symbol
to denote the rate of transfer of the g-component
from the a-fluid
phase to all other b-(fluid
and solid) phases present in the system
Write the equation and compare with my answer.

You should have no difficulty in using this fundamental balance equation for any extensive quantity of interest. In the next lecture, we'll apply this balance equation to the mass of a fluid phase.
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The As always, you can go back to the table of I'll appreciate comments and questions.
E-mail address: cvrbear@tx.technion.ac.il
qx = -
Kxx For an anisotropic porous medium: qy = Kyx
Jx + Kyy Jy
+ Kyz Jz , qz = Kzx
Jx + Kzy Jy
+ Kzz Jz .
If
lecture, TOPIC D, LECTURE 2
deals with the mass balance equation for a phase.
and choose a LECTURE.
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,
qy = - Kyy
, qz
= - Kzz
.
balance equation.
qy = Kyy Jy ,
(25)qz = Kzz Jz .
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You may e-mail me questions and comments.
E-mail address: cvrbear@tx.technion.ac.il